Question

A 200.0 g copper block absorbs 2.34 × 10^3 J of heat to raise its temperature by 30.0 K. What is the specific heat of copper? Show your work.

Answer 1

\[Q=mc\Delta T\implies c=\frac{Q}{m\Delta T}=\frac{2340}{0.2\times 30}=390 J/kg K\]

Answer 2

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