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how do we derivative 25In(x+1)???
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is it 25/x+1???????
Well, why do you think it is what you wrote?
@wio another one hELP me out plzzz:D
to be more precise, it'll be \((25\ln (x+1))' = 25 (\ln (x+1))' = 25 (1/(x+1))(x+1)'=25/(x+1)*1=25/(x+1)\) so, yes, its 25/(x+1) but using chain rule.
\((25\ln (x+1))' \\ = 25 (\ln (x+1))' \\ = 25 (1/(x+1))(x+1)'\\ =25/(x+1)*1=25/(x+1)\)
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thanks a lot:D
welcome ^_^
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