Evaluate the definite integral using the Fundamental Theorem of Calculus.

You will need accuracy to at least 4 decimal places for your numerical answer to be accepted. You can also leave your answer as an algebraic expression involving square roots.

Question

Evaluate the definite integral using the Fundamental Theorem of Calculus.

You will need accuracy to at least 4 decimal places for your numerical answer to be accepted. You can also leave your answer as an algebraic expression involving square roots.

anonymous · Answer

$$\int\limits_{1}^{3}(\frac{ d }{ dt }\sqrt{5+3t^4})dt$$

zepdrix · Answer

Hmm so this is a little different than the last one.

I think we have something like this going on.$$\large \int\limits_1^3 \frac{d}{dt}f(t)dt \qquad = \qquad \int\limits_1^3 f'(t)dt \qquad = \qquad f(t)|_1^3$$

zepdrix · Answer

$$\large = f(3)-f(1)$$

Make sense? :o

anonymous · Answer

yeah, you just took out the equation itself to understand the format

zepdrix · Answer

Yah these problems are always a little weird. We're differentiating, then anti-differentiating. So we end up with what we started with. Then we just evaluate it at the limits.

anonymous · Answer

then just go back and put the values into the function getting
$$\sqrt{248}-\sqrt{8}$$
which is right
Thanks, thats what I struggle with is where they want me to go with them

zepdrix · Answer

cool c: