NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=−4.9t^2+226t+248.

Assuming that the rocket will splash down into the ocean, at what time does splashdown occur?

The rocket splashes down after how many seconds?

How high above sea-level does the rocket get at its peak?

Question

NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=−4.9t^2+226t+248. 

Assuming that the rocket will splash down into the ocean, at what time does splashdown occur? 

The rocket splashes down after how many seconds?

How high above sea-level does the rocket get at its peak?

anonymous · Answer

no, not at all

anonymous · Answer

i dont know 23 meters maybe?

anonymous · Answer

yes. roots of that equation should give the time it lands
t = -1.07 and 47.19s

anonymous · Answer

Also, note that rockets starts from an initial height of 248m

anonymous · Answer

so, half way up means, its first derivate should be 0

anonymous · Answer

at 23.06s, its at maximum

shane_b · Answer

Good catch of the initial 248m height...distracted I guess.  Since you jumped in it's all yours.

anonymous · Answer

max. h(t)=2853.9m

anonymous · Answer

thanks alot to both of you

anonymous · Answer

double check the numbers though.