According to the following reaction, how many grams of water will be formed upon the complete reaction of 21.6 grams of oxygen gas with excess hydrogen sulfide?

2 H2S (g) + 3 O2 (g) = 2 H2O (l) + 2 SO2 (g)

Question

According to the following reaction, how many grams of water will be formed upon the complete reaction of 21.6 grams of oxygen gas with excess hydrogen sulfide?


2 H2S (g) + 3 O2 (g) = 2 H2O (l) + 2 SO2 (g)

toxicsugar22 · Answer

can you help me

anonymous · Answer

I'm not completely sure how to do this but it is a limiting reactant problem and since hydrogen sulfide is in excess, the oxygen gas must be a limiting reactant.  I know you would have to take stoichiometric ratios into account, hmmm...