Question

According to the following reaction, how many moles of water will be formed upon the complete reaction of 28.7 grams of hydrogen sulfide with excess oxygen gas?
2 H2S (g) + 3 O2 (g) = 2 H2O (l) + 2 SO2 (g)

Answer 1

molesH2S=28.7/MMH2S, that is 844.11764*10^-3

2H2S=3O2,THEN 844.11764*10^-3=XO2,WHICH IS 1.2661764

MASS OF H2O=MOLES*MM=22.791176 Grams

Answer 2

still no need to search for limiting reagent nut cracking so we ll just dive into our work

the same drill again as we ve been doing

let me check if the reaction is balanced, good

1H2O=1ZNOH2,THEN XMOLE OF H2O=0.446MOLES OF ZHOH2,WHICH IS 0.446MOLES OF H2O

NOW moles=mass/MM,therefore
mass of H2O=0.446*18=8.028 Grams

Answer 3

absolutely

Answer 4

dont worry you ll get it under your grip and it ll start begging you

Answer 5

According to the following reaction, how many moles of iron(III) chloride will be formed upon the complete reaction of 22.7 grams of iron with excess chlorine gas?

2 Fe (s) + 3 Cl2 (g) = 2 FeCl3 (s)

Answer 6

just look at it again and ask me questions on the solution that might not seem too clear

Answer 7

sorry give me a minute messed up a little here

Answer 8

ok

Answer 9

405.3571428 * 10^-3 * (56+35.5*3)=65.870535

Answer 10

65.870535 that is the answer

Answer 11

65.870535

Answer 12

did you get it

Answer 13

kind of

Answer 14

I am getting it

Answer 15

let us go through our drill this time

the limiting reagent is Fe as the question says "with excess chlorine gas" ,also the question gives you a lead by giving you only the mass of Fe

now moles of FE=mass/MM,which is 22.7/56 and value is 405.3571428 * 10^-3 from reaction if 2 Fe=2 FeCl,then 405.3571428 * 10^-3=X moles of FeCl
which means moles of FeCl= 405.3571428 * 10^-3


Moles of FeCl=mass/MM

therefore mass= 405.3571428 * 10^-3 * (56+35.5*3)= 65.870535 Grams

Answer 16

but it says inthe question "how many moles" of iron(III) chloride will be formed upon the complete reaction of 22.7 grams of iron with excess chlorine gas?

Answer 17

2 Fe (s) + 3 Cl2 (g) = 2 FeCl3 (s)

Answer 18

sorry i think i am getting tired the simple answer is 405.3571428 * 10^-3 Moles

Answer 19

let us go through our drill this time the limiting reagent is Fe as the question says "with excess chlorine gas" ,also the question gives you a lead by giving you only the mass of Fe

now moles of FE=mass/MM,which is 22.7/56 and value is 405.3571428 * 10^-3 from reaction if 2 Fe=2 FeCl ,then 405.3571428 * 10^-3=X moles of FeCl

which means moles of FeCl3= 405.3571428 * 10^-3

Answer 20

i got .4053571428

Answer 21

excellent Great JOB way to go

Answer 22

.4053571428=405.3571428 * 10^-3 ARE THE SAME THING JUST I USED MY ANDROID CALCULATOR

Answer 23

is this the anwere in moles

Answer 24

YES IN MOLES

Answer 25

thank you