According to the following reaction, how many moles of iron(III) chloride will be formed upon the complete reaction of 22.7 grams of iron with excess chlorine gas? 2 Fe (s) + 3 Cl2 (g) = 2 FeCl3 (s)
So you're going to need to do stoichometry for this. It helps to think of it as a recipe. With 2 moles of iron, and 3 moles of chlorine, you can make 2 moles of iron chloride. Do you already understand the relation of moles to mass?
So it's kind of like saying that you need two dozen eggs to make 100 pancakes, but you don't have two dozen eggs, you have 5 individual eggs. So you need to convert. The "recipe" tells you that you need two moles of iron, but you don't have moles, you have mass.
The way I always start these out is by writing what unit I need my final number to be. What are the units of your final number?
Yeah but what units will your final number be in? It's asking how many moles of iron chloride can you make. So I would write that your final value needs to be in moles of FeCl3
That isn't the answer I got
We know moles of FeCl3 is going to be our final number, so what we do has to end with moles FeCl.
We know that we have 22.7g Fe. Looking at a periodic table, we see that Fe has a mass of 55.85g for every mole.
since our final number should be moles, we can convert that now. How many moles of iron do you have with 22.7g of iron?
1 mole of iron is equal to 55.85g. We have 22.7g.
That's right! To cancel out the grams, you need to divide by grams, and then you are left with moles!
It is, but do you know why?
Awesome, thats the answer
Sure
According to the following reaction, how many moles of iron(II) chloride will be formed upon the complete reaction of 21.7 grams of iron with excess hydrochloric acid? Fe (s) + 2 HCl (aq) = FeCl2 (aq) + H2 (g)
So we have a very similar problem. They want your answer to be in "moles of iron(II) chloride)" and you are given an initial mass of one reactant. Since HCl is in excess, we don't have to worry about it.
So you have 21.7 grams of iron, how many moles is that?
.3885407341
That's right, you have .3885407341 moles of iron. An you know that for every one mole of iron, you can get one mole of FeCl2...
so this is the anser right
Yup!
thanks I understand it now
No problem! But I'm sure you're gonna have to factor sig. figs. into your answer. Don't forget to take that into account!
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