According to the following reaction, how many moles of oxygen gas are necessary to form 0.464 moles nitrogen monoxide?
4 NH3 (g) + 5 O2 (g) = 4 NO (g) + 6 H2O (g)

Question

According to the following reaction, how many moles of oxygen gas are necessary to form 0.464 moles nitrogen monoxide?
4 NH3 (g) + 5 O2 (g) = 4 NO (g) + 6 H2O (g)

anonymous · Answer

One more time

4 moles of NO= 5 moles of Oxygen, from the equation

0.464 moles NO= X moles of Oxygen
then YOU CROSS MULTIPLY 

the aim of this is to relate the actual moles given to the mole ratio of the reactants and products in the equation

this implies X moles of Oxygen =(0.464*5/4)moles