-2sin(x/2) write in a asinb(x-h) form
So I guess you're writing it in that form so you can identify the pieces, yes? \[\large -2\sin\left(\frac{x}{2}\right) \qquad = \qquad \color{orangered}{-2}\sin\left(\color{royalblue}{\frac{1}{2}}x\right)\] \[\large \color{orangered}{a}\sin\left(\color{royalblue}{b}x\right)\] Can you identify the \(\large a\) and \(\large b\) and \(\large h\) ? :)
no
can you please help me/thank you!!
I rewrote \(\large \dfrac{x}{2}\) as \(\large \dfrac{1}{2}x\). They reason we're allowed to do this is because there is always an invisible 1 on top. \[\large \frac{x}{2} \qquad = \qquad \frac{1\cdot x}{2} \qquad = \qquad \frac{1}{2}x\] Are you confused about the a and b...? I color-coded them. I thought that would have made it easier to identify them.
what i mean how to find the value of h?
please help me
\[\large \color{orangered}{-2}\sin\left(\color{royalblue}{\frac{1}{2}}x\right) \qquad =\qquad \color{orangered}{-2}\sin\left[\color{royalblue}{\frac{1}{2}}(x+0)\right]\]
Ok now it's in the form that they want. What is your h value?
0?
yesssss
thank you
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