Question

For a reaction : 2A(g) + 4B(g) → 5C(g) + 2D(l) ∆E° = 40 Kcal /mole and ∆S° = +200 Cal/K mole. The value of ∆Gº200 will be ?

Answer 1

@DLS

Answer 2

\[\LARGE \Delta G=H-T \Delta S\]

Answer 3

\[\LARGE \Delta G=40-200 \times 200\]

Answer 4

40000 hoga. 4oKCal hai. aur answer 0 nhi hai.. :/

Answer 5

rehne de.. ho gya.

Answer 6

conversion galti thi na?

Answer 7

delta S?

Answer 8

Konsi conversion? Abbe delta E is delta U not deta H . phir delta H= deltaU + dnRT se deltaH nikalo. fir us equation se answer aa jayega.

Answer 9

oh ha cont.pressure pe hota hai :P shayad

Answer 10

kya cont. pressure?

Answer 11

dono barabar hote hai shayad :/

Answer 12

constant pressure pe

Answer 13

kya hota hai const pressure pe? :o

Answer 14

1/2 ?

Answer 15

@DLS

Answer 16

Are mereko samajh nhi aa rha. Const. pressure kahan aa rha hai?

Answer 17

Yr tu kyu bezti krta hai. Tum dono. Mereko gussa aa rha hai saalon ab. :/

Answer 18

kya likh rha hai tu @DLS :O

Answer 19

Mai chala.. bye.

Answer 20

\[\LARGE \Delta U=\Delta H+ \Delta n_g RT\]FFD
agar pressure constant hai matlab WD=0 to ngrt=0
to wo dono equal hojaenge..sorry net died..:/

Answer 21

press const. to WD= 0 ..hmm
:|

Answer 22

?

Answer 23

\[\LARGE WD=-p_{external} \Delta V\]

Answer 24

V const pe WD=0 hota hai kyunki change 0 ka hota hai
P const pe, bas P const hota hai.. :P

Answer 25

\[\LARGE \Delta H=\Delta E+\Delta(PV)\]
\[\LARGE \Delta H=\Delta E +P \Delta V+V \Delta P\]
Constant pressure:
Delta P=0
V Delta P =0
fir PdV dekhte hain..if change in number of moles/volume=0 then dH=dE
dono necessary hote hain actual mein..hum VdP neglect kar dete hain zadatar kyunki pressure in constant here..par conditions to dono hai..P,V constant

Answer 26

Here,
2A(g) + 4B(g) → 5C(g) + 2D(l)
Delta N=5-6=-1
Agar ye equation hoti..
A(g)+ 4B(g) → 5C(g) + 2D(l)
to Delta N =0 hota to dono equal hote..
ya to delta N=0 ya volume constant aur pressure constant
I guess that was something obvious :P
If it was,then I'm sorry <3

Answer 27

hum Delta N ka mod lete hain na vaise?