find the solutions of the equation which lie in [o,2pi] sec x= -2 ?
Confused about the cosecant? Maybe this will cheer you up :) \[\huge \csc \ \theta=\frac1{\sin \ \theta}\]
there is sec . made a mistake
nothing for cheering me up i guess so far:)
Okay... then maybe THIS will cheer you up :) \[\huge \sec \ \theta=\frac1{\cos \ \theta}\]
yeah but what will be reference angle ?
cos x = -1\2
^That's right :) And there are only two values of x between 0 and 2pi where that's true :D
cosx = cosy x = n pie + - y
yeah you right ! but can u write those values for me :P
?
every body giving me links :D not solution of my question :(
But, it's just a matter of looking at that unit circle and pinpointing the cases where cosine equals -1/2
no usage of reference angle?
The reference angles are marked out in the unit circle :) In degrees and in radiance... for your convenience ;)
woooo thx got that i just starting to love trignometary :D
*trigonometry
Awesome :)
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