Question

What is the acceleration on the Earth? Show the calculations

Answer 1

for any object of mass m on earth, the "mg" is balanced by "mv^2/R"
equate them
\[mg=\frac{mv^2}{R}\] find g

Answer 2

v = Rw

w = 2. pi / T

Answer 3

Assuming I'm reading that answer correctly, that is wrong on like 37 different levels. I sincerely hope I'm misunderstanding that response but I am not optimistic.


You can calculate the acceleration due to gravity on earth's surface via Newton's Law of Gravitation:
\[ F = G\frac{mM}{r^2} \]
where G is the gravitational constant (~6.7 x 10^(-11) ), M and m are the masses of the earth and the object, and r^2 is the distances between the center of the earth and the object, squared.

Setting this equal to mg, we find

\[ mg = G\frac{Mm}{R^2} \rightarrow g = G\frac{M}{R^2} \]
where M is the mass of the earth and R is the radius of the earth. Your mass must be in kilograms and R must be in meters for you to get the correct answer, which you will find to be ~9.8 m/s^2.

Answer 4

distance*