Question

prove: if u is parallel to v, then [u]^2[v]^2-(u dot v)^2=0

Answer 1

one thought is use
u dot v = |u| |v| cos x
where x is the angle between the 2 vectors. in this case, x is 0 and
u dot v = |u| |v|

Answer 2

ok

Answer 3

thankyou

Answer 4

thats it?

Answer 5

then the answer is [u][v] ?

Answer 6

If the two vectors are parallel , the angle between them is 0