Why are integers rational numbers?
Ok integers are 1,2,3,etc and -1,-2,-3 etc. With me so far?
Yes
I am in 6th grade so I am just learning this stuff
Ok good. So rational numbers are numbers like the following set up: \[\frac{ a }{ b }\]
OK then a number like 1/2 or \[\frac{ 1 }{ 2 }\]
1 is called the numerator and 2 is called the denominator. The denominator (that is, the number 2) CANNOT EVER BE 0 (zero)
Do you understand this part?
Yea
OK since we've established that integers are 1,2,3, so on and -1,-2,-3 and so on...
Almost forgot, 0 itself is an integer too. but the denominator still CANNOT BE 0 (zero)
Now back to rational numbers. Rethink the numbers 0,1,2, and 3 like this: \[0=\frac{ 0 }{ 1 }; 1=\frac{ 1 }{ 1 };2=\frac{ 2 }{ 1 }; and 3=\frac{ 3 }{ 1 }\]
so since all of these numbers are actually numerators with a number 1 as their denominators, they are all rational numbers. Do you get it now young blood?
Yes
Good. That is the answer to your question and I hope that helps you out.
THose problems I did above are fractions. Forgot to tell you that too. I just named the parts of a fraction above (the numerator and the denominator)
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