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Calculate the number of moles of Al2O3 that are produced when 0.60 mol of Fe are produced in this reaction. 2Al(s) + 3FeO(s) --> 3Fe(s) + Al2O3(s) How do you do this? I've learned how to solve when you know you have like, 0.50g of a reactant but what about product?
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0.6/3=0.2 moles of Al2O3
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