Question

Please Help.......
Calculate the percent composition of
(NH4)2CO3. The correct percentages are
1. 29.15% N, 8.407% H, 12.50% C, 49.94%
O.
2. 32.74% N, 6.850% H, 15.67% C, 44.74%
O.
3. 25.65% N, 5.670% H, 12.50% C, 46.18%
O.
4. 39.15% N, 8.407% H, 12.50% C, 39.94%
O.

Answer 1

Percent Composition=Mass due to specific component/Total molar mass of compound
Then multiply it to 100...

For example i calculate the percent composition of C on CO2:

Mass due to C = 12.01 g/mol

Molar mass of compound= 12.01+2*(16)=44.01 g/mol

Percent Composition of C = (12.01/44.01)*100 = 27.29 %

Answer 2

@ cyber405 is right

Answer 3

help me please

Answer 4

in which one

Answer 5

12/96 then times 100 that is 12.5 so 2 IS WRONG

48/96 GIVES ME 50% FOR OXYGEN OR 49.94% AS IN THE ANSWER SO 1 IS CORRECT

you know why i took oxygen because it has different values in all of the ANSWER CHOICES