The amount of solar energy reaching one square meter of Earth's surface each second is 1.366 * 10^3 J. If this energy was converted into mass, how much mass in kilograms would be hitting each square meter of Earth's surface per second?

Did I do this correctly?
1.366 * 10^3 J = m * (3.00 * 10^8 m/s)^2
m = 1.366 * 10^3 J / 3.00 * 10^8 m/s)^2
m = 1.517 * 10^-5

Question

The amount of solar energy reaching one square meter of Earth's surface each second is 1.366 * 10^3 J. If this energy was converted into mass, how much mass in kilograms would be hitting each square meter of Earth's surface per second?

Did I do this correctly?
1.366 * 10^3 J = m * (3.00 * 10^8 m/s)^2
m = 1.366 * 10^3 J / 3.00 * 10^8 m/s)^2
m = 1.517 * 10^-5

jfraser · Answer

you have to square the speed of light before taking the fraction. Your order of operations is off

anonymous · Answer

Do you mean, (3.00 * 10^8 m/s)^2 is actually 9.00 * 10^16? This is what I implemented, so is my answer correct?

anonymous · Answer

I re-did it, and calculated 1.517 * 10^-13.

jfraser · Answer

10^3 over 10^16 should be way smaller than 10^-5. You are still off

jfraser · Answer

that looks better

anonymous · Answer

When dividing exponents, you subtract, so that is what I did. Is this solution correct?

jfraser · Answer

that looks right to me, without doing it out

anonymous · Answer

Okay, thank you.