Question

d/dx (e^-x2-y2)

Answer 1

Are you looking for the (implicit) derivative of \(e^{-x^2}-y^2 \), or something else?
I'm afraid your formula isn't entirely clear...

Answer 2

partial derivative, ultimately i'm trying to find the gradient.

Answer 3

OK then it is: \(\dfrac{d}{dx}e^{-x^2}-y^2\), where we consider y is a constant.
We have to use the Chain Rule:

\(\dfrac{d}{dx}e^{-x^2}-y^2=e^{-x^2}\cdot -2x=-2xe^{-x^2}\).

Answer 4

ok, thanks

Answer 5

YW!