Question

Help :(

Answer 1

\[\frac{ 8x }{x^2+2x-15 }+\frac{ 3 }{ x^2-7x+12 }\]

Answer 2

isn't 8x/(x+2)(x-5) +3/(x-3)(x-4)?

Answer 3

\[x^2+2x-15=(x+5)(x-3)\\
x^2-7x+12=(x-4)(x-3)
\]
LCD becomes simpler

Answer 4

If you factor the denominators, you get:
\(\dfrac{8}{(x-3)(x+5)}+\dfrac{3}{(x-3)(x-4)}\).

So to be able to add them, you have to make the new denominator: \((x-3)(x+5)(x-4)\)

Answer 5

so is it 11/(x-3)(x+5)(x-4)?

Answer 6

\[\frac{8x(x-4)+3(x+5)}{(x-3)(x+5)(x-4)}
\]

Answer 7

Do I cancel out anything T:

Answer 8

\[\frac{8x^2-29x+15}{(x-3)(x+5)(x-4)}
\]

Answer 9

Answer was: 8x^5/(x+5)(x-4)