Question

solve for x
\[\frac{ 1 }{ \sqrt{1-x ^{2}} }=\frac{ \pi }{ 12 }\]

Answer 1

\[\sqrt{1-x^{2}} = \frac{ 12 }{ \pi }\]
\[1-x^{2} = \frac{ 12^{2} }{ \pi^{2} }\]
\[x = \sqrt{1 - \frac{ 12^{2} }{ \pi^{2} }}\]

Answer 2

thanks so much

Answer 3

Welcome!