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OpenStudy (anonymous):
(4xy^3-8x^3y^2-8y^2)/(4xy)
jimthompson5910 (jim_thompson5910):
Hint:
you can break up
(4xy^3-8x^3y^2-8y^2)/(4xy)
to get
(4xy^3)/(4xy) - (8x^3y^2)/(4xy) - (8y^2)/(4xy)
OpenStudy (anonymous):
I really want a fully solved example of this. Not a hint.
OpenStudy (anonymous):
Or at least show me step by step.
jimthompson5910 (jim_thompson5910):
Simplify (4xy^3)/(4xy) and tell me what you get
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OpenStudy (anonymous):
xy^2 ?
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
- (8x^3y^2)/(4xy) simplifies to _____
OpenStudy (anonymous):
2x^2y
jimthompson5910 (jim_thompson5910):
close
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OpenStudy (anonymous):
xy^2-2x^2y is the equation?
jimthompson5910 (jim_thompson5910):
yes you have it so far, just one more to do
OpenStudy (anonymous):
2/1x^2y?
jimthompson5910 (jim_thompson5910):
-(8y^2)/(4xy) simplifies to -2y/x
jimthompson5910 (jim_thompson5910):
so
(4xy^3)/(4xy) - (8x^3y^2)/(4xy) - (8y^2)/(4xy)
turns into
y^2 - 2x^2y - 2y/x
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jimthompson5910 (jim_thompson5910):
sorry above I meant to say that (4xy^3)/(4xy) turns into y^2 (and NOT xy^2)
OpenStudy (anonymous):
uh...
jimthompson5910 (jim_thompson5910):
where are you stuck?
OpenStudy (anonymous):
the full final equation is y^2-2x^2y-2y/x ?
jimthompson5910 (jim_thompson5910):
correct, it's an expression (not an equation), but you get the idea
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OpenStudy (anonymous):
so thats it? O;
jimthompson5910 (jim_thompson5910):
yes
OpenStudy (anonymous):
Oh, Thank you.
jimthompson5910 (jim_thompson5910):
yw
OpenStudy (anonymous):
(4xy^3-8x^3y^2-8y^2)/(4xy)
Factor 4y^2 from the top.
(4y^2(xy - 2x^3 - 2))/(4xy)
Now using Exponent law for division, we can reduce the y^2 to just y in the numerator and we can cancel out the 4.
(y(xy - 2x^3 - 2))/(x)
You can expand the numerator to get:
(-2x^3y + xy^2 - 2y) / (x)
That's the final expression. Not much more for you to do.
@ikoreanx3