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The letter i represents the imaginary number √-1. Note that i1=i, i2=-1, i3=-i, i4=1, i5=i,… Use patterns to simplify i2987
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do you know the basics of Complex number ?
no
They just rotate, around and around, by 90 degrees each time. Good times!
take the integer remainder when dividing 2987 by 4
since 4 divides 2484 evenly, the remainder is 3
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making \(i^{2987}=i^3=-i\)
I like @satellite73 answer much better than what I am about to write, but if modular stuff still seems yucky then you can try this too. 1. i^2987 2. i * i^2986 3. i * (i^2)^1493 4. i * (-1)^[something odd, so remains -1] 5. i * -1 = -i 6. But seriously, the other answer is more elegant in my opinion.
thank you everyone :)
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