From the enthalpies of reaction below, calculate the heat of the reaction:
3H2(g) + O3(g) → 3H2O(g)

From:
2H2(g) + O2(g) → H2O(g) ΔH = –484 kJ
3O2(g) → 2O3 (s) ΔH = +285 kJ

Question

From the enthalpies of reaction below, calculate the heat of the reaction:
3H2(g) + O3(g) → 3H2O(g)

From:
2H2(g) + O2(g) → H2O(g)      ΔH = –484 kJ
3O2(g) → 2O3 (s)                  ΔH = +285 kJ

anonymous · Answer

Could you also show the steps on how you would change the equations?

anonymous · Answer

isnt there a value lacking or did i read the question wrong

anonymous · Answer

You probably read it wrong....

anonymous · Answer

it is correct

anonymous · Answer

look at the image well

anonymous · Answer

I have the answer key to this and that solution is wrong. I don't understand how to solve this problem. Can someone else help?

anonymous · Answer

the only thing wrong there is the math ,just correct the math that is all

anonymous · Answer

...i am thoroughly confused. Is it possible for you to clarify your steps again please? I don't understand the diagram very well.

anonymous · Answer

let me give an answer and you tell me if it is the answer just a minute

anonymous · Answer

-855

anonymous · Answer

get back to me so i can dose off

anonymous · Answer

You are close but not quite the right answer.

anonymous · Answer

what do you mean

anonymous · Answer

It's not the right answer basically. your number is close to the correct answer but it's not it.

anonymous · Answer

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