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OpenStudy (anonymous):
well is it x to the 2 9ths or it it x to the 2 divided by 9
OpenStudy (anonymous):
\[\frac{ x^2 }{ 9 }-\frac{ y^2 }{ 4 }=1\] that is the equation
OpenStudy (anonymous):
wait I think this is past my level of understanding. I'm sorry and I wish I could help. I don't think I know what eccentricity means. If you still want I could try, if not maybe give the medal to someone else.
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
e = c/a
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OpenStudy (anonymous):
since it is a hyperbola
c^2 = a^2 + b^2
OpenStudy (anonymous):
a = 3
b = 2
OpenStudy (anonymous):
yeah i figure that much but my answer is wrong i wonder what is the right answer?
OpenStudy (anonymous):
c= sqrt (9 +4) = sqrt (13)
e = sqrt(13)/3
OpenStudy (anonymous):
well my answer is\[\frac{ \sqrt{5} }{ 3 }\] oh it should \[\sqrt{13}\] not\[\sqrt{5}\] thanks
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