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Help with finding f^-1 (x)
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f(x)= \[\sqrt[3]{x-7}\]
you would need to switch the x's and y's in your equation
step1; cube both sides
and then solve for y
step2; isolate x
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step3; replace y with x and vice versa
so f^-1 would look like y = cubed root of x - 7 x = cubed root of y -7 so you would cube both sides x^3 = y-7 add 7 to both sides y = x^3 + 7
so f^-1 (x) would be x^3+7?
Once you replace y with x and x with y and solve for y, you have found the inverse.
that would be correct.....as @calmat01 has said...one you have swtiched the x's and y's...then solved for y again..you have found the inverse
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