Question

7x - 3y = 4

2x - 4y = 1

Which of the following systems is not the same as solving the system shown?
@johnweldon1993

Answer 1

can you complete the question

Answer 2

if you need to solve for x and y, then it shouldnèt be bad

Answer 3

multiply first equation with -4 and second equation with 3 and add the two to solve for x, once you have that you can find y easily

Answer 4

yeah...is there more to the question? or are we just solving for x and y again??

Answer 5

this is the all of question and answer choices 7x - 3y = 4

2x - 4y = 1

Which of the following systems is not the same as solving the system shown?


28x- 12y= 16 and -6x+ 12y= -3
14x- 6y= 4 and -14x+ 28y= 1
-28x+ 12y= -16 and 28x- 56y= 14

Answer 6

okay there we go
so

7x - 3y = 4

2x - 4y = 1

so with answer choice 2... it looks like we multiply the top equation by 2....and the bottom by -7...so lets do that

14x - 6y = 8 and -14 + 28y = -7

hmmm..doesn't look the same as the answer choice right? must not be correct :)

Answer 7

Solve the following system of equations by the substitution method.

10x + 10y = 1

x = y - 3

What is the value of y?

Answer 8

substitution....well look you already now what x equals dont you?

x equals y - 3

you SUBSTITUTE this into the first equation wherever you see an x so

10(y-3) + 10y = 1

distribute that 10
10y - 30 + 10y = 1

combine those 10y's

20y - 30 = 1
add 30 to both sides

20y = 31
divided both sides by 20

y = 31/20

Answer 9

Which of the following equations could be the result of using the comparison method to solve the system shown?

x + 2y = 6

x - 4y = 8