Question

Find exact value: tan(π/6 + π/4)
how to plug into Sum and difference formula

Answer 1

\[\tan(\frac{ \pi }{ 6} + \frac{ \pi }{ 4 }) \]

Answer 2

using formula \[\tan \left( a + b \right)=\left(\begin{matrix}\frac{ tanA +tanB }{ 1- tanA \times tanB} \\ \end{matrix}\right)\]

Answer 3

You have all the information you need, just find the tan(pi/6) and the tan(pi/4) then plug in your values into the formula.

Answer 4

i dont know what value is tan ... I know how to do sin / cos but not tan..

Answer 5

*tan is

Answer 6

Well, just take your value of sine, and divide it by cosine, because that is the definition of tangent.

Answer 7

\[\tan \frac{ \pi }{ 6 }=\frac{ \sin \frac{ \pi }{ 6 } }{ \cos \frac{ \pi }{ 6 } }\]

Answer 8

and do the same for tan(pi/4)

Answer 9

If you have your unit circle committed to memory, then all you have to do is take your y @ 30 degrees, and divide by your x @ 30* to find your tan(pi/6).

Answer 10

sorry I had to take a break for a min. thank you!

Answer 11

No Problem. Anytime.

Answer 12

:( ... I still dont understand how to set this up.
I answer key say answer is \[\frac{ \sqrt{3}+ 1 }{ \sqrt{3} - 1}\]

Answer 13

*the answer key states that correct answer is:

Answer 14

ok, let's compute each expression piece by piece.

Answer 15

Takes me forever to use equation tool

Answer 16

tan(pi/6) = (1/2) / (sqrt3 / 2)

Answer 17

good

Answer 18

so the 2's cancel, leaving you 1 over rad 3.

Answer 19

tan(pi/4)= (sqrt2)/(sqrt2)

Answer 20

which simplifies to 1.

Answer 21

So, this is what we have:

\[\frac{ 1-\frac{ 1 }{ \sqrt{3} } }{ 1-\frac{ 1 }{ \sqrt{3} } } \]

Answer 22

oops

Answer 23

I mean + on top.

Answer 24

1+1/rad 3

Answer 25

ok, lemme start this again so as not to confuse you.

Answer 26

not that hard at all. haha. Just looks intimidating

Answer 27

ok, so did you understand how the final result was obtained or do you need to see the steps?

Answer 28

I understand, cheers!

Answer 29

great! Glad I helped...somewhat...lol