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Mathematics 7 Online
OpenStudy (anonymous):

differentiate the function f(x)= xln(x)-x

OpenStudy (zehanz):

Use the Product rule: (uv)' = u'v+uv'

OpenStudy (zehanz):

Of course the derivative of the "-x" part is just -1, so you have to use the Product Rule for xlnx

OpenStudy (anonymous):

Where the derivative of ln(x)=1/x

geerky42 (geerky42):

Yeah, \(\large ln(x)=\dfrac{1}{x}\).

OpenStudy (zehanz):

So we get: \(f'(x)=1 \cdot \ln x+x \cdot \dfrac{1}{x}-1\). What does this simplify to?

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