Mathematics
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OpenStudy (anonymous):
Find the volume of the solid when rotated about the y-axis.
y=3-x^2/9
x=3
the answer is 45/2 pi
can you show me how to get that answer? thank you
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OpenStudy (anonymous):
Is that x the only thing over 9 or is it the whole expression over 9?
OpenStudy (anonymous):
you are posting this again
OpenStudy (anonymous):
yea i dont get it still
OpenStudy (anonymous):
its only x^2 that is over 9
OpenStudy (anonymous):
Was it answered already @aajugdar ?
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OpenStudy (anonymous):
ok.
OpenStudy (anonymous):
well
OpenStudy (anonymous):
you got the points
find equation with x^2
integrate it from 0 to 3
OpenStudy (anonymous):
ok x^2= 9y-27 but when i integrate it im not getting the right answer
OpenStudy (anonymous):
let me see
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OpenStudy (anonymous):
Your 9y-27 is not correct.
OpenStudy (anonymous):
it should be 27-9y
OpenStudy (anonymous):
\[\int\limits_{3}^{0}\]isnt that the same thing
OpenStudy (anonymous):
@electrokid
OpenStudy (anonymous):
I am getting 81 pi /2
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OpenStudy (anonymous):
That's the answer I got.
OpenStudy (anonymous):
am i doing this right? \[\int\limits_{3}^{0} \pi(27-9y)^2 - \pi(3)^2 \]
OpenStudy (anonymous):
(162-81)/2*pi
OpenStudy (anonymous):
I can't read that, my laptop is currently processing mass at 0% so I can't read anything from the equation editor...and is being snarky!
OpenStudy (anonymous):
math*
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OpenStudy (anonymous):
hang on...trying the other method.
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
Does that say
\[y=3-\frac{1}{9}x^2?\]
OpenStudy (anonymous):
ya
OpenStudy (anonymous):
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