Question

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Answer 1

Square roots cannot be negative so the interval will have to start at...

Answer 2

thats how they gave me the question

Answer 3

sorry i meant x cannot be negative. This means that \[x \ge ?\]

Answer 4

That will be the lower bound of your interval

Answer 5

its x-6

Answer 6

so it's \[f(x) = \sqrt{x - 6}\]?

Answer 7

yes

Answer 8

right so \[x-6 \ge ?\] considering that we cannot take the square root of a negative number?

Answer 9

explain

Answer 10

To find the lower part of the interval you must find where the x values start right? As there is a square root We cannot use negative values of x-6. This means that \[x-6 \ge 0\] and \[x \ge 6\] This is where the function's domain starts

Answer 11

The domain will go up to infinity however does not include infinity so make sure you use the right interval sign.\[[6,\infty)\]

Answer 12

sorry got to go hope that helped :/