A hot air balloon 70 meters above the ground is falling at a constant rate of 6 meters per second while another hot air balloon 10 meters above the ground is rising at a constant rate of 15 meters per second. To the nearest tenth of a second, after how many seconds will the 2 balloons be the same height above the ground?
Let x be the number of seconds until they are the same height. Height of first balloon: 70-6x
Do you understand that?
Yes,I know why your writing the equation like that
Then you write the expression for the height of the balloon that is rising.
will that equatin be 10+15x ?
Yes. Very good. Now set the two heights equal and solve for x
but what should i be plugging in for x? what amount of seconds?
Did you write the equation that says the two heights are equal?
Height of first balloon: 70-6x Height of second balloon: will that equatin be 10+15x
Set the two heights equal to each other and solve. Remember the problem asks: after how many seconds will the 2 balloons be the same height above the ground? And x is : Let x be the number of seconds until they are the same height.
I got 2.85771 as my answer?
What did the directions say to do with your answer?
"TO THE NEAREST TENTH* so then that will be 2.8 ?? i think
What is the next digit after the 8?
5. Will the final answer be then 2.85 ?
So should you round the 8 up to 9 or leave it an 8?
round it up! then it will be 2.9
yep
thanks
yw
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