What is an equation of a parabola with the given vertex and focus?
vertex: (–2, 5); focus: (–2, 6)

Question

What is an equation of a parabola with the given vertex and focus? 
vertex: (–2, 5); focus: (–2, 6)

anonymous · Answer

|dw:1363576396537:dw|

anonymous · Answer

since both the $x$ values are the same, you know the $x$ term is squared 
also because the focus is above the vertex, you know if faces up 
see the lousy picture

anonymous · Answer

equation therefore has the form 
$$(x-h)^2=4p(y-k)$$ where $(h,k)$is the vertex
so you know it looks like 
$$(x+2)^2=4p(y-5)$$ and all you need is $p$

anonymous · Answer

from 5 to 6 is one unit up, making $p=1$ and so $4p=4$

anonymous · Answer

and your equation is $(x+2)^2=4(y-5)$ you can check it here http://www.wolframalpha.com/input/?i=+parabola+%28x%2B2%29^2%3D4%28y-5%29

anonymous · Answer

Sorry I had to step away from the computer. I'm still a bit confused. What's the outcome of this is supposed to look like?