Question

how would you get the equation of the line that passes through the point (6, -2) and has a slope of -2/3?

Answer 1

If you know the Point-Slope form, you just write it down. What are the chances you know that form?

Answer 2

y-y1=m(x-x1)+b where m is your slope and b is your intercept.
So if you plug in your point (6,-2) and your slope m=-2/3 then this is what you'll get:
y-(-2)=-2/3(x-6)
y+2=-2/3(x-6)
\[y+2=-\frac{ 2 }{ 3 }x+4\]
\[y=-\frac{ 2 }{ 3 }x+2\]
Hope that helped!

Answer 3

?? Get that "+b" out of there and you'll be right on.

Answer 4

Oh whoops, my bad! Yup, the correct equation is y-y1=m(x-x1). :)

Answer 5

thank you so much!!!