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Mathematics 16 Online
OpenStudy (anonymous):

Please help with these!!! I have been trying for hours and it is just not clicking! It's Calculus by the way. 1) y=5x^4 + 24x^3 + 24x^2 +7 is concave for? 2) The first derivative of the function f is given by f^'=(sin^2(x)/x)-(2/9) How many critical values does f have on the open interval (0,10) 3) If y=3x+6 what is the min. value of (x^3)y 4) If f^''(x)=(x-1)(x+2)^3(x-4)^2, then the graph of f has inflection points when x= 1, -2, or 4 (could be more than one) Please answer what you can! I would be so grateful you have no idea.

OpenStudy (anonymous):

for #1: take the second derivative. The sign of the second derivative is the concavity.

OpenStudy (anonymous):

I am having trouble with derivatives. Sounds silly and is madly unfortunate considering that derivatives make up most of Calculus.

OpenStudy (anonymous):

you know the rule for derivatives of polynomials?

OpenStudy (johnweldon1993):

well for #1 just use the power rule d/dx x^n is nx^n-1 do this for all the terms....then do it again for the 2nd derivative because the determines concavity

OpenStudy (anonymous):

^ like john said.

OpenStudy (anonymous):

Okay, thank you. Any clue on the others?

OpenStudy (anonymous):

#2... what are critical values?

OpenStudy (anonymous):

I haven't the slightest clue. I tried looking it up but nothing was clear in how to find them.

OpenStudy (anonymous):

should we assume they are the same as critical points?

OpenStudy (anonymous):

So when the tan line is horizontal, or doesn't exist?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Okay, that would make a lot more sense!

OpenStudy (anonymous):

for #3, sketch y=3x+6 and (x^3)y

OpenStudy (anonymous):

for #4, the graph has an inflection point whenever the second derivative equals zero. They give you the second derivative there, so they basically gave you the answer.

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