A moving body undergoes uniform acceleration while travelling in a straight line between points X,Y and Z. The distance XY and YZ are both 40m. The time to travel from X to Y is 12s and from Y to Z is 6.0s.
What is the acceleration of the body?
a)0.37
b)0.49
c)0.56
d)1.1

Question

A moving body undergoes uniform acceleration while travelling in a straight line between points X,Y and Z. The distance XY and YZ are both 40m. The time to travel from X to Y is 12s and from Y to Z is 6.0s. 
What is the acceleration of the body?
a)0.37
b)0.49
c)0.56
d)1.1

anonymous · Answer

YZ:
d=40
t=0.6
v0=?
a=?

d=v0*t+0.5at^2
40=0.6v0+0.5*a*0.36
=>0.6*v0+0.18*a = 40
v0 = (40-0.18*a)/0.6

XY:
v0 = ?
d=40
t=12
v=v0 of YZ
a=?
d = v0*y+0.5a*t^2
but v0 = v-a*t
so,
d = v-a*t+0.5*a*t^2
40=....

substitute and solve

anonymous · Answer

Thank you so much! :)