Simplify the given expression.
\[\sqrt{-6} \times \sqrt{-18}\]
well, it confuses me a bit. Is it possible that \[\sqrt{-6}\] isn't even possible
You know, if you have \[\sqrt{a}\] and \[\sqrt{b}\] you will get \[\sqrt{a}*\sqrt{b}=\sqrt{ab}\] But I am not sure if it can be -6 ...
@hartnn can you explain it?
@franknbeans , this belongs to topic complex numbers , right ?
are you learning complex numbers at school?
\(\sqrt{a}*\sqrt{b}=\sqrt{ab}\) thiis is true if and only if , a and b are positive numbers or 0
@franknbeans are you still here?
for, \(\sqrt{-a}.\sqrt{-b}=\sqrt{-1}\sqrt{a}\sqrt{-1}\sqrt{b}=i\sqrt{a}i\sqrt{b}=i^2\sqrt{ab}\) since, \(i=\sqrt{-1}, i^2=-1\) \(\sqrt{-a}.\sqrt{-b}=-\sqrt{ab}\)
Hey sorry everyone. I appreciate the help, I crashed after this because I was up all night working. Thanks again. :)
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