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I have the answer can someone please check me.... Find the derivative t(x)=e^3x+1
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is it \(t(x)=e^{3x+1}\)
or \(t(x)=e^{3x}+1\)
that was the answer that I got too the first post you did but I wasn't sure because it is the same as the problem
hold on that was not my answer at all, that was me trying to clarify the question
oh gotcha yes that is the question
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which one? post one or post two?
post one is the question
\[t(x)=e ^{3x+1}\]
then by the chain rule you get \[\frac{d}{dx}e^{f(x)}=f'(x)e^{f(x)}\] in you case you have \(e^{3x+1}\) so the derivative is \(3e^{3x+1}\)
ok I wan't sure if the 3 came on front or not
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don't forget the 3 out front, because you need to multiply by the derivative of \(3x+1\)
ok thanks
yw
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