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Mathematics 7 Online
OpenStudy (anonymous):

I have the answer can someone please check me.... Find the derivative t(x)=e^3x+1

OpenStudy (anonymous):

is it \(t(x)=e^{3x+1}\)

OpenStudy (anonymous):

or \(t(x)=e^{3x}+1\)

OpenStudy (anonymous):

that was the answer that I got too the first post you did but I wasn't sure because it is the same as the problem

OpenStudy (anonymous):

hold on that was not my answer at all, that was me trying to clarify the question

OpenStudy (anonymous):

oh gotcha yes that is the question

OpenStudy (anonymous):

which one? post one or post two?

OpenStudy (anonymous):

post one is the question

OpenStudy (anonymous):

\[t(x)=e ^{3x+1}\]

OpenStudy (anonymous):

then by the chain rule you get \[\frac{d}{dx}e^{f(x)}=f'(x)e^{f(x)}\] in you case you have \(e^{3x+1}\) so the derivative is \(3e^{3x+1}\)

OpenStudy (anonymous):

ok I wan't sure if the 3 came on front or not

OpenStudy (anonymous):

don't forget the 3 out front, because you need to multiply by the derivative of \(3x+1\)

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

yw

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