Question

Have a problem buddies! please solve it!

Answer 1

Draw graph of following linear equation on the same axes
(i)x+y=3
(ii)3x-2y=4

Also shade the region formed by their graphs and y- axis

Answer 2

@satellite73

Answer 3

pls help

Answer 4

@agostino

Answer 5

@Soumyadeep help karo yaar!

Answer 6

get a table of value for each and sketch the graph

Answer 7

Please elaborate your answer.

Answer 8

For x+y=3, by rearranging, we have y=3-x.
By substituting y=0 and x=0, we have y and x-intercepts respectively.

Answer 9

Similarly, for 3x-2y=4, by rearranging, we have x and y-intercepts. You can try to sketch the graph yourself by just connecting x-intercept and y-intercept together and extend it!

Answer 10

hey @agostino thanks man! please can you explain it in easy way than this!

Answer 11

The simplest way to tell you is because all the equations above are straight lines. From this, we can just find where the line cross the y-axis (y-intercept) and the x-axis (x-intercept) respectively.
We can just connect these two points then we have a straight line described by the equation.

Answer 12

But my teacher said that each equation should have 3 solutions. Can u pls provide

Answer 13

pls pls

Answer 14

@agostino pls can u

Answer 15

I don't really understand the part of "3 solutions"

Answer 16

Equations are equations, and 2 equations in 2D give you 1 solution, which is the coordinate of their intersection, unless they are parallel to each other.

Answer 17

Man! you gotta replace the x or y values with the numbers, I feel that part difficult

Answer 18

The technique is rather simple.

Consider an equation ax+by+c=0

You need at least 2 points to sketch a straight line.

To do so, we set either x=0 or y=0.

If we have y=0, we have ax+c=0, x=-c/a

If we have x=0m we have by+c=0, y=-c/b

Then you connect the points (-c/a,0) and (0,-c/b) and there you go, a straight line.