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Help please? What is the boiling point of a solution containing .852 g naphthalene (C1C0H8, molar weight 128.2 g/mol) dissolved in 14 g benzene? The boiling point of pure benzene is 80.10 degreed Celsius and the boiling point constant is 2.53 C/m.
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\[\Delta T_b = K_b*m\]plug into the equation and solve
I tried that, but I'm not getting the right answer. Can I get a little more explanation? Thanks!
show your work, ill tell you where you went wrong
I have delta T =(2.53)*(6.6x10^-3) And I got 80.25 as my final answer but I just don't think it's correct...
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