Question

I have the answer can someone please check me.....
Find the derivative
h(x)=sin^3x

Answer 1

The question problem is\[h(x)=\sin^3x\]

Answer 2

By chain rule,\[\frac{d\sin^3 x}{dx}=\frac{d\sin^3 x}{d\sin x}\frac{d\sin x}{dx}=3\sin^2 x \cos x\]

Answer 3

Is that what you got?

Answer 4

yes that is what I got too:)