Question

I have the answer can someone please check me....
Which function has the following as its derivative
b'(x)=cos(3x)

Answer 1

\[
b(x)=\int\cos(3x)dx\\
\text{set}\quad u=3x\implies dx=\frac{du}{3}\\
b(u)=\int\cos(u)\frac{du}{3}=\frac{\sin u}{3}+C
\]

Answer 2

I got (1/3)sin(3x) is that correct

Answer 3

\[\frac{ 1 }{ 3 }\sin(3x)\]

Answer 4

yes...
do not forget the "+C"
it is indefinite integrals

Answer 5

what do you mean can you show me what is would look like

Answer 6

can someone please tell me if the answer I gave is correct

Answer 7

oh ok

Answer 8

@MATTW20 you are on the opposite side of the river.

Answer 9

wtf

Answer 10

@MATTW20 re-read the question
@farmergirl411 you are good. what you go is correct.

Answer 11

oh my fault misread

Answer 12

so then cansomeone please clarify what the answer is

Answer 13

you had the right answer

Answer 14

(1/3)sin(3x) is that what is right

Answer 15

@MATTW20 do not confuse the poor childrean!! ;ol

Answer 16

lol yeah sorry bout that

Answer 17

@farmergirl411
Remember, that for "indefinite integrals", i.e., when the integration has no bounds, you always have to retricean unknown constant term (call it C)

Answer 18

so is what I posted what the answer is correct when you say the C part I am getting really confused

Answer 19

so, you exact answer should be..
\[
b(x)=\frac{1}{3}\sin(3x)+C
\]
VERIFICATION:
try to find b'(x).. should give you the question back...

Answer 20

ok thanks