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Mathematics 9 Online
OpenStudy (anonymous):

Can someone please help me with this math problem

OpenStudy (anonymous):

OpenStudy (anonymous):

g'(4) = - 1/2

OpenStudy (anonymous):

ok I got that answer too

OpenStudy (anonymous):

because the derivative of a linear function is its slope.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

what did you get for h'(6)

OpenStudy (anonymous):

I am not sure. What did you get?

OpenStudy (anonymous):

I got 1.5

OpenStudy (anonymous):

How did you do it?

OpenStudy (anonymous):

I got it bylooking at the graph I;m not sure if it is right or not

OpenStudy (anonymous):

derivative is slope of tangemt. also, remember that at maxima or minima, that slope is "0"

OpenStudy (anonymous):

g(x) is maximum at x=4

OpenStudy (anonymous):

we already figered out that g'(4)=-.5

OpenStudy (anonymous):

for the other two, get the equation of f(x) and g(x) has two equation

OpenStudy (anonymous):

no. g'(4)=0

OpenStudy (anonymous):

@electrokid Explain

OpenStudy (anonymous):

oh ok I guess I don't understand how to do the problem can you help

OpenStudy (anonymous):

@farmergirl411 I do not understand how you can possibly get "-.5"!

OpenStudy (anonymous):

scroll up a bit and you se my explanation for g'(4)

OpenStudy (anonymous):

@electrokid the formula for the line is f(x) = -1/2x + c so its derivate is going to be -1/2

OpenStudy (anonymous):

@Boblovesmath you gave the answer for f'(4) ... not g'(4)

OpenStudy (anonymous):

Oh okay, I am sorry

OpenStudy (anonymous):

@Boblovesmath guys, you are confusing the heck off the kids!! lol

OpenStudy (anonymous):

dude do you know how to get the equation for g(x). I know it is abosulte value.

OpenStudy (anonymous):

@farmergirl411 ok, so, now, put the equations for f(x) and g(x) please.

OpenStudy (anonymous):

ok I can't get I keep messing it yup can you explain it too me.

OpenStudy (anonymous):

\[ g(x)=x,\quad\forall\,0\le x\le4\\ g(x)=8-x,\quad\forall\,4\le x\le8\\ \]

OpenStudy (anonymous):

oh ok I had 8+x so I was sort of close

OpenStudy (anonymous):

now, h(x)... around x=6:: \[h(x)=-{8-x\over2}+4\] so, the slope now is..?

OpenStudy (anonymous):

I got -1

OpenStudy (anonymous):

remember, is a function decreases, slope (in fact, its derivative) is negative..

OpenStudy (anonymous):

no, h'(6)=-1/2=-0.5

OpenStudy (anonymous):

@electrokid Kisses bro

OpenStudy (anonymous):

@Boblovesmath no thank you.

OpenStudy (anonymous):

oh sorry I forgot to type the 2 I had that

OpenStudy (anonymous):

ok.. similarly, go for the m(x).. remember that there, x<4

OpenStudy (anonymous):

@Boblovesmath you can use absolute value thingy but I personally like to keep things simple and use as much less brain as I can

OpenStudy (anonymous):

does m'(2)=0.5

OpenStudy (anonymous):

I did not do it. but if you can show your m(x), I can tell

OpenStudy (anonymous):

@farmergirl411 remember the "cube" part....

OpenStudy (anonymous):

@farmergirl411 c'mon, poke.. poke

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