I have a right triangle, and I need to solve for tan∠A - csc∠C = 3x .

AB is 5
BC is 7
I got the hypotenuse using the Pythagorean Theorem, which is 8.60.
So, AC is 8.60.

Angle B is 90*, while Angle A is greater than Angle C. I have a feeling Angle A is 60* and Angle C is 30*. I will post the image below. :c Please help!!

Question

I have a right triangle, and I need to solve for tan∠A - csc∠C = 3x .

AB is 5
BC is 7
I got the hypotenuse using the Pythagorean Theorem, which is 8.60.
So, AC is 8.60.

Angle B is 90*, while Angle A is greater than Angle C. I have a feeling Angle A is 60* and Angle C is 30*.  I will post the image below. :c Please help!!

anonymous · Answer

attachment

anonymous · Answer

$$\tan (\theta) = \frac{ opposite }{ adjacent }$$ Use this formula. The opposite side is 7 and the adjacent is 5, so plug these values in to find the angle.

anonymous · Answer

Tan would be 1.4?

anonymous · Answer

Then getting csc would be hypotenuse/opposite. So, 8.60/7=1.228!

anonymous · Answer

Then it would be tan-csc=3x; 1.4-1.228=3x?

anonymous · Answer

Yeah that's it :P

anonymous · Answer

$$\tan (1.4)-\csc (1.228) = 3x$$