4. Identify the center and intercepts of the conic section. Then find the domain and range. graph of circle intercepts six (1 point)
The center of the circle is (6, 6). The x-intercepts are (6, 0) and (–6, 0). The y-intercepts are (0, 6) and (0, –6). The domain is {y | 6 ≤ y ≤ –6}. The range is {x | 6 ≤ x ≤ –6}. The center of the circle is (6, 6). The x-intercepts are (6, 0) and (–6, 0). The y-intercepts are (0, 6) and (0, –6). The domain is {x | –6 ≤ y ≤ 6}. The range is {y | –6 ≤ x ≤ 6}. The center of the circle is (0, 0). The x-intercepts are (6, 0) and (–6, 0). The y-intercepts are (0, 6) and (0, –6). The domain is {x | –6 ≤ x ≤ 6}. The range is {y | –6 ≤ y ≤ 6}. The center of the circle is (0, 0). The x-intercepts are (6, 0) and (–6, 0). The y-intercepts are (0, 6) and (0, –6). The domain is {y | 6 ≤ y ≤ –6}. The range is {x | 6 ≤ x ≤ –6}.
ts a circle.. all the info right there.. center.. guess domain -> what are the possible values of "x" for which you see the graph see anything beyong -6 and 6? range-> same as domain but for "y" intercepts.. points wehre the graph crosses the axes... there are 4 such points
u lost me there ^
@electrokid can u show me how to get the answer step by step???
center... around what point do you see the symmetry of the given circle?
6 and -6 ?
no .. how did you get that though? "center" central point of the figure...
when you draw a circle, one tip of the compass is the center, the other "draws" the circle
0 0
good. next, domain.... the circle you see, are for what values of "x"... are the values of "x" limited?
6=<y=<6 ????
perfect.. -6<=x<=6 same thing for range.. but now, look for "y"
-6=<x=<6 ???
yes.. looking at the graph, we see that the circle exists only for -6<=x<=6
thank you!
when writing a range, always write the smaller one on the left and bigger one on the right
I got that. can u help me with another prob?
What are the focus and the directrix of the graph of x =1/24 y^2 ? (1 point) focus (0, –6), directrix x = 6 focus (6, 0), directrix x = –6 focus (0, 6), directrix y = –6 focus (–6, 0), directrix y = 6
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