Question

At 9:00 on Saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path.The bicyclist heading north is riding 4 km/hour faster than the bicyclist heading south. At 10:15, they are 40 km apart. Find the two bicyclists’ rates

Answer 1

Let the speed of the south-bound bicyclist = s
Then speed of north-bound bicyclist = s + 4
The separation speed = s + s + 4 = 4 + 2s ...............(1)
Distance travelled in 1.25 hours = 40 km
Therefore separation speed = 40/1.25 ..............(2)
The two values of separation speed in (1) and (2) must be equal.
4 + 2s = 40/1.25
5 + 2.5s = 40 ..............(3)
Now you need to solve equation (3) to find the value of s.
Speed of north-bound bicyclist = s + 4

Answer 2

need answer

Answer 3

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