A beam of electrons moves at right angles to a magnetic field of 4.5 × 10^-2 tesla. If the electrons have a velocity of 6.5 × 106 meters/second, what is the force acting on the electrons? The value of q = -1.6 × 10^-19 coulombs.Select one of the options below as your answer: A. -2.9 × 106 N B. -4.9 × 10^-14 N C. -4.9 × 10^-14 N D. -6.5 × 10^-13 N

Question

carniel · Answer

Plz help :'(

anonymous · Answer

F = Bqv sin theta
F=Force 
B=magnetic flux density
q=charge
v=velocity
theta=angle the moving electrons make with the magnetic field.

anonymous · Answer

do you understand it now??

carniel · Answer

Not really :(

carniel · Answer

Can u plz explain what I'm suppose to do to find the answer in a clear mannor. Really trying to specialize in Physics.

anonymous · Answer

you are finding the force so using that formula,
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