Question

solve:
0.25 = log16^x

Answer 1

\[\log _{a}b =y\]
is the same as writing
\[a ^{y} =b\]

Answer 2

a=10?

Answer 3

yes

Answer 4

so now its 10^(0.25) = 16^x

Answer 5

yes...that is it

Answer 6

now what hahah

Answer 7

log16^x = x log 16

Answer 8

so play the 10^(0.25) on a calculator

Answer 9

right, thats 1.77827

Answer 10

from there, you can do the reverse of what i first wrote.......realise what you have is in the form \[a ^{y} = b\]

Answer 11

so you can rewrite in the log form to find x..

Answer 12

do you understand what i am saying???

Answer 13

kind of except i dont know what to write..

Answer 14

.25 = log(2^(4x))
using log rules you can bring the 4x out front:
.25 = 4xlog(2)
log(2) is a number so:\[\frac{ .25 }{ 4*\log(2) } = x\]