Question

solve:
3^(x-1) 13 years ago

Answer 1

\[3^{x-1} \le 2^{x-7}\]

Answer 2

right

Answer 3

step1; take log of both sides
step2; isolate x

Answer 4

how do you take the log of both sides?

Answer 5

\[(x-1)\log3 \le (x-7)\log2\]

Answer 6

I used log exponent law to bring it to the front

Answer 7

\[xlog3-xlog7 \le \log3-7\log2\]

Answer 8

\[x \le \frac{ \log3-7\log2 }{ \log3-\log2 }\]

Answer 9

there was a typo in 2nd last step, instead of x log 7 it should be x log 2

Answer 10

a bunch of magic just happened but i got it down so thank you very much!