PLEASE HELP!!! (Algebra)
The ratio of the numerator to the denominator of a fraction is 2 to 3. If both the numerator and the denominator are increased by 2, the fraction becomes 3/4. How do I figure the original fraction?
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OpenStudy (anonymous):
thank you for coming over! can you help me?
OpenStudy (phi):
you could say
\[ \frac{n}{d} =\frac{2}{3} \]
\[ \frac{n+2}{d+2}= \frac{3}{4} \]
OpenStudy (anonymous):
yes, so how do i solve for the original fraction?
OpenStudy (phi):
do you know how to cross multiply ?
OpenStudy (anonymous):
yes. what should i cross multiply?
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OpenStudy (phi):
first 2 steps: cross multiply both equations
what do you get ?
OpenStudy (anonymous):
in the first one you get
3n/2d
in the second one you get
4n + 8/3d + 6
OpenStudy (phi):
not / but =
3n= 2d
4n+8= 3d+6
OpenStudy (anonymous):
ok
OpenStudy (phi):
use the first equation to solve for n
n= (2/3) d
use that for n in the 2nd equation
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