Question

I am off for today guys
good night
and here is 1 sum
find area of surface obtained by
y=2sqrt(x)
4<=x<=9
about x axis

Answer 1

no1 knows?

Answer 2

\[\huge \frac{ 76 }{ 3 }\]

Answer 3

what equation did you use?

Answer 4

what did you integrate

Answer 5

what is the answer?
given

Answer 6

let me know how you solved ? O.o no answer is given

Answer 7

iam wrong !

Answer 8

w8 let me solve it

Answer 9

total area = sum of perimeters all the small tiny circles from x=4 to x=9

Answer 10

so integrating from 4 to 9 in terms of y=

Answer 11

\[\int\limits_{4}^{9}2\sqrt{x}\]

Answer 12

and a correction for thickness.... times,
\[\sqrt{1+y'(x)}dx\]

Answer 13

the element has a thickness dx so, gotta account for that

Answer 14

wait
I didn't get that

Answer 15

\[
S=2\pi\int_xy\sqrt{1+y'^2}dx
\]

Answer 16

that's the final equation?